(20/(x-4))^2+8(20/(x-4))+16=0

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Solution for (20/(x-4))^2+8(20/(x-4))+16=0 equation:


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(20/(x-4))^2+8*(20/(x-4))+16 = 0

(20^2)/((x-4)^2)+(8*20)/(x-4)+16 = 0

(20^2)/((x-4)^2)+(8*20*(x-4))/((x-4)^2)+(16*(x-4)^2)/((x-4)^2) = 0

8*20*(x-4)+16*(x-4)^2+400 = 0

16*x^2+160*x-128*x-240+256 = 0

16*x^2+32*x+16 = 0

16*x^2+32*x+16 = 0

16*(x^2+2*x+1) = 0

x^2+2*x+1 = 0

DELTA = 2^2-(1*1*4)

DELTA = 0

x = -2/(1*2)

x = -1 or x = -1

16*(x+1)^2 = 0

(16*(x+1)^2)/((x-4)^2) = 0

(16*(x+1)^2)/((x-4)^2) = 0 // * (x-4)^2

16*(x+1)^2 = 0

x+1 = 0 // - 1

x = -1

x in { -1, -1 }

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